In collision free protocol channel efficiency is given by-
A. D/(d + log2(n))
B. D*(d + log2(n)) C. Log2(n) D. (d + log2(n))
Explanation: In collision free protocol channel efficiency is given by d/(d + log2(N)).
In collision free protocol channel efficiency is given by- | D/(d + log2(n)) | CSS, PMS, PPSC, FPSC, KPPSC, SPSC, ISSB and NTS Past Papers | Pakistan's Largest Online Past Papers Database