In collision free protocol channel efficiency is given by-

A. D/(d + log2(n))

B. D*(d + log2(n))
C. Log2(n)
D. (d + log2(n))

Explanation: In collision free protocol channel efficiency is given by d/(d + log2(N)).

In collision free protocol channel efficiency is given by- | D/(d + log2(n)) | CSS, PMS, PPSC, FPSC, KPPSC, SPSC, ISSB and NTS Past Papers | Pakistan's Largest Online Past Papers Database

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