A. Adding an extent (another chunk of contiguous space)
B. Adding an index table to the first contiguous block
C. Adding pointers into the first contiguous block
D. None of the mentioned
A. Internal fragmentation
B. External fragmentation
C. Starvation
D. All of the mentioned
A. Stack
B. Linked list
C. Data
D. Pointer
A. Fat
B. Linked allocation
C. Hashed allocation
D. Indexed allocation
A. External ? fragmentation & size ? declaration
B. Internal ? fragmentation & external ? fragmentation
C. Size ? declaration & internal ? fragmentation
D. Memory ? allocation & size ? declaration
A. Partition
B. Address
C. File
D. All of the mentioned
A. Supports
B. Does not support
C. Is not related to
D. None of the mentioned
A. Less than
B. Equal to
C. Greater than
D. Keeps varying with
A. Only one
B. At least two
C. Exactly two
D. None of the mentioned
Explanation: We can easily keep the initial address of the file in memory and calculate immediately the disk address of the ith block and read it directly.
A. 10000110000001110011111100011111?
B. 110000110000001110011111100011111?
C. 01111001111110001100000011100000?
D. 001111001111110001100000011100000?