| Freshers | Network Security Interview |
| Network Hardware | Experienced |
| Classful Addressing |
A. 2msec
B. 4msec
C. 2sec
D. 4sec
Explanation: Average frame transmission time Tfr = 200 bits/200 kbps or 1 ms Vulnerable time = 2x Tfr = 2 × 1 ms = 2 ms.
A. Errorless delivery
B. Variation in the packet arrival time
C. Timely delivery of message
D. None of the mentioned
Explanation: ‘Jitter’ refers to variation in the packet arrival time.
A. True
B. False
C.
D.
Explanation: The statement is true.
A. Mesh
B. Star
C. Bus
D. Ring
Explanation: This is the disadvantage of mesh topology.
A. 1
B. N(n+1)/2
C. N
D. N(n-1)/2
Explanation: There are N(N-1)/2 links for N nodes.
A. Mesh
B. Star
C. Bus
D. Ring
Explanation: The star topology has a single hub.
A. Mesh
B. Star
C. Bus
D. Ring
Explanation: In the bus topology, fault identification is tougher.
A. Mesh
B. Star
C. Bus
D. Ring
Explanation: Ethernet LANs use bus topology,
A. Mesh
B. Star
C. Bus
D. Ring
Explanation: The ring topology uses the token passing algorithm. The token holder gets its turn at communication.
A. N(n-1)/2
B. N
C. N+1
D. None of the mentioned
Explanation: N drop lines and 1 bus line.