A. 1.10101e+13
B. 1.10101e+13
C. 1.10101e+13
D. 1.10101e+13
Explanation: Solve using polynomial division and then appending the remainder to the divisor.
A. 92 frames
B. 368 frames
C. 276 frames
D. 151 frames
Explanation: G =1 S=G×e−G=0.368 (36.8%) Throughput = 1000 × 0.0368 = 368 frames.
A. 1.10e+24
B. 1.10e+24
C. 1.00e+25
D. 1.10e+24
Explanation: Bit stuffing involves adding a 0 after every five 1s during transmission.
A. Switch
B. Hub
C. Gateway
D. Proxy server
Explanation: A switch is a device that splits large networks into smaller segments, decreasing the number of users sharing the same network resources and bandwidth.
A. 1.846 mbps
B. 1.536 mbps
C. 2.4 mbps
D. None of the mentioned
Explanation: Average No, of lines u=in each page = 24 Each line has 80 char. Each char required 8 bits 100 x 24 x 80 x 8 = 1,536,000=1536 Mbps.
A. True
B. Is use
C.
D.
Explanation: Nsub = n + log2(N/Nsub) is used to find the prefix length.
A. 880
B. 879
C. 881
D. 801
Explanation: Total data bytes = total length – header length = 80 bytes in this datagram. Last byte is therefore 879.