A. 0.8
B. 0.5
C. 0.66
D. 0.75
Explanation: Total number of bytes in the header = 5 x 4 = 20 bytes. Total length = 0028_16 = 40 bytes. Data carried by the packet = (40 – 20) = 20 bytes. Efficiency = payload length / total length = 20/40= 50%.
A. 3
B. 4
C. 5
D. 6
Explanation: The first 4-bits show the version i.e. 0100 -> version 4.
A. 4
B. 8
C. 12
D. 16
Explanation: The right 4-bits multiplied by 4 is the header length (0010=2). 2 x 4 = 8.
A. 16
B. 64
C. 32
D. 8
Explanation: HLEN = 1000 = 8. 8 x 4 = 32 bytes.
A. 10
B. 40
C. 60
D. 20
Explanation: Total number of bytes in the header = 5 x 4 = 20 bytes. Total length = 0028_16 = 40 bytes. Data carried by the packet = (40 – 20) = 20 bytes.
A. 2
B. 5
C. 3
D. 1
Explanation: In an IPv4 header, the TTL is the 9th byte (or the 17th and 18th hexadecimal digits) which is one when counted from right to left. (or the 17th and 18th hexadecimal digits).
A. 128.11.5.32
B. 128.11.3.31
C. 127.11.3.32
D. 127.12.5.31
Explanation: Converting the binary value to their respective decimal values yields 128.11.3.31.