Q
In collision free protocol channel efficiency is given by-
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A
A. D/(d + log2(n))
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B
B. D*(d + log2(n))
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C
C. Log2(n)
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D
D. (d + log2(n))
Correct Answer:
A. A. D/(d + log2(n))
Explanation:
In collision free protocol channel efficiency is given by d/(d + log2(N)).