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Network Security Interview
Experienced
Q
Find the number of addresses in a range if the first address is 146.102.29.0 and last address is 146.102.32.255.
AA. 1028
BB. 1024
CC. 578
DD. 512
Correct Answer:
B. B. 1024
Explanation:
Subtract the first address from the last address in base 256. The result = 0.0.3.255 Therefore, number of addresses = (3 X 256 + 255) + 1 = 1024.
