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Network Security
Socket Secure Layer I
Q
Consider the following example – Size of Plaintext – 48 bytes. Size of MAC – 20 bytes. Block Length – 8 bytes. How many bytes of padding need to be added to the system?
AA. 1
BB. 2
CC. 3
DD. 4
Correct Answer:
C. C. 3
Explanation:
48 + 20 = 68 bytes. 72 is the next multiple of 8 (Block Length). 72 – 68 = 4. But we need to compensate 1 byte for length of the padding. Therefore, we require only 3 Bytes padding.
