Q
A router receives a packet with the destination address 132.7.21.84. Find the network address of the packet.
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A
A. 1.32.7
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B
B. 132.7
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C
C. 13.27
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D
D. 21.84
Correct Answer:
B. B. 132.7
Explanation:
132 is between 128 and 191, so it is Class B address i.e. n=16-bit. Therefore, Network address 132.7 Host address 21.84.